 ### LeetCode - Arrays - Minimum Absolute Difference

Given an array of distinct integers `arr`, find all pairs of elements with the minimum absolute difference of any two elements.

Return a list of pairs in ascending order(with respect to pairs), each pair `[a, b]` follows

• `a, b` are from `arr`
• `a < b`
• `b - a` equals to the minimum absolute difference of any two elements in `arr`

Example 1:

```Input: arr = [4,2,1,3]
Output: [[1,2],[2,3],[3,4]]
Explanation: The minimum absolute difference is 1. List all pairs with difference equal to 1 in ascending order.```

Example 2:

```Input: arr = [1,3,6,10,15]
Output: [[1,3]]
```

Example 3:

```Input: arr = [3,8,-10,23,19,-4,-14,27]
Output: [[-14,-10],[19,23],[23,27]]```
```class Solution {     public List<List<Integer>> minimumAbsDifference(int[] arr) {         List<List<Integer>> resultList = new ArrayList<List<Integer>>();         Arrays.sort(arr);         //System.out.println(Arrays.toString(arr));         //System.out.println("Min Diff >> "+(arr-arr));         int min_diff = arr-arr;         int counter = 1;         while(counter<arr.length){             if(arr[counter]-arr[counter-1] < min_diff){                 min_diff = arr[counter]-arr[counter-1];                 resultList.clear();             }             if(arr[counter]-arr[counter-1] == min_diff){                 List<Integer> temp = new ArrayList<Integer>();                 temp.add(arr[counter-1]);                 temp.add(arr[counter]);                 resultList.add(temp);             }             counter++;         }         return resultList;     } }```